5d^2+5d-3=2d^2

Solution for 5d^2+5d-3=2d^2 equation:

5d^2+5d-3=2d^2

We move all terms to the left:

5d^2+5d-3-(2d^2)=0

determiningTheFunctionDomain
5d^2-2d^2+5d-3=0

We add all the numbers together, and all the variables

3d^2+5d-3=0

a = 3; b = 5; c = -3;
Δ = b2-4ac
Δ = 52-4·3·(-3)
Δ = 61
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{61}}{2*3}=\frac{-5-\sqrt{61}}{6}
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{61}}{2*3}=\frac{-5+\sqrt{61}}{6}
$